The gear train shown is arranged to feed lumber between the two 6-in-diameter rollers (R ) into a cutting blade for the purpose of ripping the lumber. The blade is being directly driven at 500 rpm. A power takeoff which consists of the belt system shown drives the rollers for the purpose of feeding the stock. Determine the speed of the stock in ft/min and the direction of stock movement.

If it is hard to understand this figure, here is it explained:

The saw blade is in the lower left rotating clockwise at 500RPM. The 6in diameter of the saw blade is irrelevant. What is relevant is the 4in diameter pulley on the same shaft as the saw and therefore also running at 500RPM. This 4in pulley is attached by a self-crossing belt to an 18in diameter pulley. The crossing has no effect on the speed but reverses the direction. The 18in pulley is on the same shaft as the 12in pulley and so these rotate at the same RPM. The 12in pulley drives a 14in pulley with a non-crossing belt, so these two rotate in the same direction. On the same shaft as the 14in pulley is gear 1, a 10tooth gear, so gear 1 rotates at the same angular velocity as the 14in pulley. Gear 1 is enmeshed with a 40tooth gear 2 which is in turn enmeshed with a 60tooth gear 3. Gear 3 is compounded with 10tooth gear 4, this means they are on the same shaft rotating at the same angular velocity. 10tooth gear 4 is enmeshed with 65tooth gear 5. Gear 5 is compounded with the 6in diameter roller R.